F(-3)=2x^2+3

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Solution for F(-3)=2x^2+3 equation: 



(-3)=2F^2+3

We move all terms to the left:

(-3)-(2F^2+3)=0

We add all the numbers together, and all the variables

-(2F^2+3)-3=0

We get rid of parentheses

-2F^2-3-3=0

We add all the numbers together, and all the variables

-2F^2-6=0

a = -2; b = 0; c = -6;
Δ = b2-4ac
Δ = 02-4·(-2)·(-6)
Δ = -48
Delta is less than zero, so there is no solution for the equation

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